Question

sin^4 45 + cos^2 45 - cos^2 45 divided by cosec 45 + sec 45+cot 60

Answer 1

Answer:

The answer is 0

Step-by-step explanation:

Using standard values

$\frac{\sin^445^\circ+\cos^445^\circ-\cos^245^\circ}{\cos ec45^\circ+\sec 45^\circ+\cot 60^\circ}\\=\frac{(\frac{1}{\sqrt 2})^4+(\frac{1}{\sqrt 2})^4-(\frac{1}{\sqrt 2})^2}{\sqrt 2+\sqrt 2+\frac{1}{\sqrt 3}}\\=\frac{\frac{1}{4}+\frac{1}{4}-\frac{1}{2}}{2\sqrt 2+\frac{1}{\sqrt 3}}=0$