Question

sin=4/5 find the value of 3 sec-5cos​

Answer 1

hey mate:

given here:

sinx =4/5.

so,

cos x=√(1- sin^2x)

=√(1-16/25)

=√9/25

= 3/5

and,sec x= 5/3

so,

3sec x - 5cos x= 3× 5/3 - 5×3/5

=5-3

=2.

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