sin ^4 theta - cos ^4 theta = sin^2 theta - cos ^2 theta
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Answered by
6
LHS = ( sin⁴∅ -cos⁴∅)
=( sin²∅ -cos²∅)(cos²∅ +sin²∅)
we know ,
sin²∅ + cos²∅ = 1
=(sin²∅ -cos²∅).1 = RHS
=( sin²∅ -cos²∅)(cos²∅ +sin²∅)
we know ,
sin²∅ + cos²∅ = 1
=(sin²∅ -cos²∅).1 = RHS
anant6:
thnx bro
i was not getting the idea about a^2-b^2 = a+b *a-b
:-)
Answered by
1
Answer:
salty acid basic.............
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