Question

sin 4 theta + cos 4 theta upon 1 minus 2 sin square theta cos square theta is equal to 1

Answer 1

Let us take theta equal to x for out convenience.

Now LHS=
Sin4x + cos4x / 1 - 2sin2x × cos2x

Simplifying the numerator -

Sin4x + cos4x = ( sin2x + cos2x ) ^ 2 - 2 × sin2x × cos2x
= (1)^2 - 2 sin2x cos2x
{ Bcz sin2x + cos2x = 1 }
= 1 - 2 × sin2x × cos2x

Now as numerator = denominator
They will cancel each other and will be equal to 1.

So LHS = 1 = RHS.
H/P.

HOPE IT HELPS.
PLZ MARK BRAINLIEST.