sin^4 x - cos^4 x = 1- cos^2 x
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Answered by
7
Hey !!!
we know that a² - b² = ( a + b ) ( a - b ) same here
sin⁴x - cos⁴x =( sin²x + cos²x ) ( sin²x -cos²x )
=> 1 ( sin²x - cos²x )
=> ( 1 - cos²x - cos²x ) •°• 1 - cos²x = sin²x
hence , ( 1 - 2cos²x ) Answer..
please check out ur question . I think given RHS is wrong .
_______________________
Hope it helps you !!!
@Rajukumar111
we know that a² - b² = ( a + b ) ( a - b ) same here
sin⁴x - cos⁴x =( sin²x + cos²x ) ( sin²x -cos²x )
=> 1 ( sin²x - cos²x )
=> ( 1 - cos²x - cos²x ) •°• 1 - cos²x = sin²x
hence , ( 1 - 2cos²x ) Answer..
please check out ur question . I think given RHS is wrong .
_______________________
Hope it helps you !!!
@Rajukumar111
Answered by
2
= 1 - cos ^2x
L.H.S = R.H.S (PROVED)
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L.H.S = R.H.S (PROVED)
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