sin(40)-cos(70)=root3cos(80)
Answers
Answered by
1
Answer:
Hey mate,
Step-by-step explanation:
→ L.H.S. :- sin 40 - cos 70 using sin C - sin D 2cos C + D /2 sin C-D/ 2
→ sin 40 - cos ( 90 - 20)
→ sin40−sin20
→ 2cos30.sin10. sin(90−80)=cos80
→ 2 √3 /2 X cos 80
→ √ 3 cos 80 ° R .H. S
hope it was helpful
Similar questions