Question

sin 40 degree by 2 Cos 60 degree minus 2 sec 41 degree by 3 cos 45 degrees equal to what

Answer 1

Trigonometry by complementary angles

Answer 2

Answer:

-1/6

Step-by-step explanation:

Prerequisites:

• Sin A = Cos ( 90 - A )  
• Cosec A = Sec ( 90 - A )

According to the question,

Sin 40 can be written as : Cos ( 90 - 40 ) = Cos 50

And Cosec 49 can be written as Sec ( 90 - 49 ) = Sec 41

Substituting the values we get,

$\implies \dfrac{Cos 50}{2\: Cos50} - \dfrac{2\:Sec41}{3\:Sec41}$

Cancelling out terms we get,

$\implies \dfrac{1}{2} - \dfrac{2}{3} \\\\\text{Taking LCM we get,}\\\\\implies \dfrac{3 - 4}{6} = \dfrac{-1}{6}$

Hence the answer is -1/6

Thanks !!