Question

sin 40 =
tan 90° =
​

Answer 1

Answer:

Tan 90° =infinite

Sin 40=???

Sin30 =1/2

Hope it will help you

Thank you

Plz mark brainlist

Answer 2

Answer:

OX or OX'.

Since, ∠YOB = ∠XOA

Therefore, ∠OEF = ∠COD.

Now, from the right-angled ∆EOF and right-angled ∆COD we get, ∠OEF = ∠COD and OE = OC.

Hence, ∆EOF ≅ ∆COD (congruent).

Therefore, FE = OD, OF = DC and OE = OC.

Trigonometrical Ratios of (90° - θ)

4Save

In this diagram FE and OD both are positive. Similarly, OF and DC are both positive.

plz follow me