Question

sin (40+theta) - cos (40-theta) =​

Answer 1

sin(40

0

+θ)cos(10

0

+θ)−cos(40

0

+θ)sin(10

0

+θ)=sinAcosB−cosAsinB,

Where (40

0

+θ)=A and (10

0

+θ)=B

sin(A−B)=sin{(40

0

+θ)−(10

0

+θ)}=sin30

0

=

2

1

Answer 2

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