sin( 40 + x) cos( 10+x) - cos ( 40 + x) sin( 10+ x) = 1/2
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Let A= 40+x and B= 10+x
In Lhs of above question SinAcosB - cosAsinB
Since, SinAcosB - cosAsinB is equal to sin(A-B)
And sin(A-B) = sin(40+x-10-x)= sin(30)= 1/2
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Since Lhs = rhs
Hence proved....
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