Question

sin (40°+x)cos (10°+x)-cos(40°+x)sin(10°+x)​

Answer 1

Answer:

let 40°+x be A and 10°+x be B

SinA cosB - CosA sinB

so

SinA cosB - CosA sinB = Sin(A-B)

substituting the value of A and B

=> Sin(A-B) = Sin(40°+x - [10°+x])

=> Sin(40°+x -10° -x) =Sin(30° +0) = Sin(30°) (40°-10° = 30° and x-x =0)

Sin 30° = 1/2

Hope this helps