Sin 45+ tan^2 60+ tan^2 45
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1/√2 + (√3)^2 + (1)^2
=1/√2 + 3 + 1
= 1/√2 + 4
=(1+4√2)/√2
Answered by
0
Answer:
(1/√2 + 4)
Step-by-step explanation:
since sin 45 = 1/√2
tan 60 = √3
tan 45 = 1
now put all the values in the equation
1/√2 + (√3)² + (1)² = 1/√2 + 3 + 1
= (1/√2+ 4)
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