Question

sin (45° + 0) - cos (45°- 0) is equal to
(a) 2coso (b) 0 (c)2sino (d) 1​

Answer 1

$\bf\large\underline\pink{Answer:-}$

0

Explanation :-

Sin ( 45 + A ) = Sin 45 . Cos A + Cos 45 . Sin A   => Equation 1

Cos ( 45 - A ) = Cos 45 . Cos A + Sin 45 . Sin A   => Equation 2

According to the question,

To prove, Equation 1 - Equation 2 = 0

=> Sin 45 . Cos A + Cos 45. Sin A - Cos 45 . Cos A - Sin 45 . Sin A = 0

Evaluating, Cos 45 and Sin 45 as 1 / √2 we get,

=> 1 / √2 * Cos A + 1 / √2 * Sin A - 1 / √2 . Cos A - 1 / √2 . Sin A = 0

Taking 1 / √2 common we get,

=> 1 / √2 [ Cos A + Sin A - Cos A - Sin A ] = 0

=> [ 1 / √2 ] [ 0 ] = 0

=> 0 =0