sin ( 45°+A) - cos( 45°-A) is equal
Answers
Answered by
2
Step-by-step explanation:
=sin(45°+A)-cos(45°-A)
=sin45°cosA+cos45°sinA - (cos45°cosA+sin45°sinA)
=1/√2cosA+1/√2sinA -(1/√2cosA+1/√2sinA)
=1/√2cosA+1/√2sinA-1/√2cosA-1/√2sinA
=0
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Answered by
4
Answer:
sin(45°+A) - cos(45°-A)
⇒sin5° cosA+cos45° sinA−cos45° cosA−sin45° sinA
= 1 (cosA+sinA−cosA−sinA)
√2
=0
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