sin (45° + θ) – cos (45° – θ) is equal to
(A) 2cosθ (B) 0 (C) 2sinθ (D) 1
NCERT Class X
Mathematics - Exemplar Problems
Chapter _INTRODUCTION TO TRIGONOMETRY AND ITS APPLICATIONS
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6
sin45* + sinФ - cos45* + cosФ
= 1/√2 +sinФ -1/√2 + cosФ
= sinФ + cosФ
= cos(90* - Ф) + cosФ
= cos90* - cosФ + cosФ
= cos90*
= 1
Ans- (D) 1
= 1/√2 +sinФ -1/√2 + cosФ
= sinФ + cosФ
= cos(90* - Ф) + cosФ
= cos90* - cosФ + cosФ
= cos90*
= 1
Ans- (D) 1
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2
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