Math, asked by narenkavi388, 2 months ago

Sin 45°+Sin 90
I + COS 45°+ COS 909​

Answers

Answered by rajeebsc001
0

Answer:

Sin 45°+Sin 90 = 1/√2 + 1 = (1+√2)/ √2

= (1+1.414) / 1.414

= 2.414 / 1.414

= 1.707

I + COS 45°+ COS 909 = 1+1/√2+0

= (1+1.414) / 1.414

= 2.414 / 1.414

= 1.707

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