sin(45°+theta)-cos(45°-theta)=
Answers
Answered by
10
use A instead of theta
sin(45°+A)-cos(45°-A)
sin45.cosA+cos45.sinA-cos45.cosA-sin45.sinA
=1/√2.cosA+1/√2.sinA-1/√2.cosA-1/√2.sinA
=0
sin(45°+A)-cos(45°-A)
sin45.cosA+cos45.sinA-cos45.cosA-sin45.sinA
=1/√2.cosA+1/√2.sinA-1/√2.cosA-1/√2.sinA
=0
Answered by
4
Refer above for the answer
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