Question

(sin 47/cos43)^2 + (cos 43/sin 47)^2 - 4cos^2 45

Answer 1

(Sin47/cos43)^2+(cos43/sin47)^2 - 4cos^2 45 =>(Sin47/sin47)^2+(sin47/sin47)^2 - 4cos^2 45

[where cos 43 = sin47 as cos theta = Sin (90 -theta ) . Here cos 43

= sin (90 - 43)

= sin47 ] => 1 + 1 - 4 × (1/ root 2)^2 [ cos 45 = 1/root 2] => 2 - 4×(1/2)

=> 2- 2

=> o.

Answer = 0

Answer 2

Heyy buddy!!

This is what you asked for.

I hope it will be helpful.