Question

Sin 47 degree by cos 43 degree to the whole square + cos 30 degree by cot 30 degree to the whole square minus sin 60 degree to the whole square

Answer 1

Step-by-step explanation:

Given Sin 47 degree by cos 43 degree to the whole square + cos 30 degree by cot 30 degree to the whole square minus sin 60 degree to the whole square

• Given (sin 47 degree / cos 43 degree)^2 + (cos 30 degree / cot 30 degree)^2 – (sin 60 degree)^2
• So (sin 47 / cos(90 – 47) )^2 + (cos 30 x sin 30 / cos 30)^2 – (√3 /2)^2
• So (sin 47 / sin 47)^2 + (sin 30)^2 – ¾
• So (1)^2 + (1/2)^2 – ¾
• 1 + ¼ - ¾  
• 4 + 1 – 3 / 4
• = 1/2

Reference link will be

https://brainly.in/question/15924587

Answer 2

There is final answer of this question 1/2.

1) first of all write the question in the mathematical terms as given below.

2) (sin 47° / cos 43°)² + (cos 30°/ cot 30°)² – (sin 60°)²

=(sin 47° / cos(90 – 47)° )² + (cos 30° x sin 30° / cos 30°)² – (√3 /2)²

= (sin 47° / sin 47°)² + (sin 30°)² – ¾

= (1)² + (1/2)² – ¾ ( Putting the values of the trigonometric terms here)

=1 + ¼ - ¾  

=(4 + 1 – 3) / 4

= 1/2

3) Value of the above given expression is 1/2.