sin 49 degree sec 41 degree + cos 49 degree cos sec 41 degree find the value
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sec41°sin49°+cos29°cosec61°-2/√3(tan20°tan60°tan70°)]/[3(sin²31°+sin²59°)]
=[sec41°sin(90°-41°)+cos29°cosec(90°-29°)-2/√3{tan20°×√3×tan(90°-20°)}]/
[3{sin²31°+sin²(90°-31°)]
=[sec41°cos41°+cos29°sec29°-2(tan20°cot20°)]/[3(sin²31°+cos²31°]
=(1+1-2)/(3×1)
=0
=[sec41°sin(90°-41°)+cos29°cosec(90°-29°)-2/√3{tan20°×√3×tan(90°-20°)}]/
[3{sin²31°+sin²(90°-31°)]
=[sec41°cos41°+cos29°sec29°-2(tan20°cot20°)]/[3(sin²31°+cos²31°]
=(1+1-2)/(3×1)
=0
sundeep4321:
dont know
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