sin 4a + sin 5a + sin 6a/ cos 4a + cos 5a + cos 6a= tan5a
Attachments:

Answers
Answered by
10
check the answer
I am sure it will help you
I am sure it will help you
Attachments:

Answered by
3
Answer:
as given in the question
has to be equal to tan5A
to prove that
by using the formula
sin C + sin D = 2 sin( ) .
cos C + cos D = 2 cos .
there fore y using the formula
=>
Taking sin 6A as C and 4A as D so that the value is perfectly divided
=>
Now , take common sin 5A in the numerator and cos 5A in the denominator
=>
by cancelling ( 2 cos A +1) in the numerator and the denominator
gives us
=>
=>
hence proved
To learn more about Trigonometric equation :
https://brainly.in/question/6820230
#SPJ3
Similar questions