Math, asked by vinodarmyji555, 10 months ago

sin^4Q+sin^2Qcos^2Q=sin^Q

Answers

Answered by prashansa15

1

Step-by-step explanation:

I m giving you a shot... It will help you

Attachments:

Answered by oorvi

0

Answer:

LHS= sin^Q(sin^Q+cos^2Q)

sin^Q(1) (sin^Q+cos^Q= 1)

sin^Q= RHS

Step-by-step explanation:

In the fist step take common of sin^Q

Then can continue easily

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