(sin^4thea-cos^4thea+1)cosec^2thea=2
Answers
Answered by
0
click on the image attachedn
Attachments:
Answered by
0
(sin⁴x - cos⁴x + 1)cosec²x
((sin²x+cos²x)(sin²x - cos²x)+1)cosec²x (a+b)(a-b)=(a²-b²)
(sin²x-cos²x + 1)1/sin²x sin²x + cos²x = 1
1-cot²x+1/sin²x
1+cosec²x - cot²x cosec²x - cot²x = 1
1+1
2
PLZ MARK AS BRAINLIEST.
Similar questions