Math, asked by abhishek883, 8 months ago

(sin^4thea-cos^4thea+1)cosec^2thea=2

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Answered by sanketj

click on the image attachedn

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Answered by jainishpjain

(sin⁴x - cos⁴x + 1)cosec²x

((sin²x+cos²x)(sin²x - cos²x)+1)cosec²x (a+b)(a-b)=(a²-b²)

(sin²x-cos²x + 1)1/sin²x sin²x + cos²x = 1

1-cot²x+1/sin²x

1+cosec²x - cot²x cosec²x - cot²x = 1

1+1

PLZ MARK AS BRAINLIEST.

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