Math, asked by sgurwinder4596, 10 months ago

Sin^4x+cos^4x=1-sin^2x*cos^2x

Answers

Answered by dorgan399

5

Step-by-step explanation:

sin⁴x+cos⁴x

=sin⁴x+cos⁴x+2sin²x cos²x-2sin²x cos²x

=(sin²x+cos²x)²-2sin²xcos²x

=1-2sin²xcos²x

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