Math, asked by anuragverma75075, 10 months ago

sin 50° cos 85°=1-√2 sin 35° ​

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Answered by azizalasha
1

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solved

Step-by-step explanation:

2 Sin 50° cos 85°= sin 135° + sin -35°​ = sin 135° - sin 35°  = 1/√2 - sin 35°

2 Sin 50° cos 85° = (1 - √2sin 35°)/√2

Sin 50° cos 85° = (1 - √2sin 35°)/2√2

Answered by Anonymous
1

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hope it will be helpful...

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