sin 50°-sin 70° + sin 10º =
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Answer:
Step-by-step explanation:
We will use these two trignometric formulas to solve this.=
1) Sin(A+B) = Sin(A)Cos(B)+Cos(A)Sin(B)
2) Sin(A-B) = Sin(A)Cos(B)-Cos(A)Sin(B)
Now we write our expression as Sin(60-10) - Sin(60+10) +Sin(10).
On applying the above formulas we get:
Sin(60)Cos(10) - Cos(60)Sin(10) -{Sin(60)Cos(10) + Cos(60)Sin(10)} + Sin(10)
On simplifying we get:
-2*Cos(60)Sin(10) + Sin(10)
Using Cos(60) = 1/2 in above expression we get:
-2*(1/2)*Sin(10) + Sin(10)
= 0
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