Question

sin(50°+theta)-sin(25°-theta)=0​

Answer 1

Step-by-step explanation:

Sin(50+theta)- cos (40-theta)

= sin(90-40+theta) - cos(40-theta)

=sin[90-(40-theta)]- cos(40-theta)

=cos(40-theta)-cos(40-theta) since sin(90-theta)=cos theta

=0

Answer 2

Step-by-step explanation:

transfer sin(25°-theta) to other side...

then the equation would be like...

sin(50°+theta)=sin(25°-theta)

now cancel sin from both sides...

so we'll have...

50°+theta=25°-theta

2theta=-25

theta=-25/2°

hope it helps...

if i am wrong then plz mention in the comment!☺️☺️