sin(50° + thita) cos(10° − thita) + cos(50° + thita) sin(10° − thita) =
√3/2
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Answer:
Here we got sin(50+theta) cos(10-theta) + cos(50+theta) sin(10- theta) = √3/2, hence proved, Here we can't solve for theta because theta got cancelled, Hence theta can be any value. Hope this helps you.
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