Question

sin 52+ sin68+ sin172=??

Answer 1

hey mate here is your answer

sin52° + sin68° + sin172°

so, sin(60-8) + sin(60+8) + sin(180-8)

now by using sin(a+b)=sina.cosb+sinb.cosa
and sin(a-b)=sina.cosb - sinb.cosa
and ASTC rule

we get

sin60.cos8-sin8cos60+sin60.cos8+sin8cos60 + sin8

put value of known one

√3/2.cos8 + √3/2.cos8 + sin8

√3.cos8+sin8

hope it will help you

mark me brainliest ✌✌✌