Question

sin 52°+cot38°\sin 38°+cos 52°=tan 52°

Answer 1

sin52+cot(90-38)/sin38+cos(90-52)=tan52
=sin52+sin52/sin38+sin38=tan52 
=0

Answer 2

Sin52°+Cos38°/Sin38°+Cis52° = Tan52°

LHS = SIN 52°+COS 38°/SIN38°+COS 52°

Sin52°+ Cos(90-52°)/Sin38°+Cos(90-38)°

Sin52° + Sin52° / Sin(90-52°)+ Cos52° [ Cos(90-theta=Sin theta]>

2Sin52°/2Cos52° = Sin52°/Cos 52°

SIN52°/COS 52° = TAN52° [ SIN THETA/ COS THETA= TAN THETA]

HENCE,

LHS = RHS