Question

sin (540 + theta). cos (270 + theta) .tan (720 - theta)

Answer 1

Let, theta = A, for the sake of simplicity...

So, we have :-

=> sin(540° + A). cos(270° + A). tan(720° - A)

=> - sin(A). sin(A). [-tan(A)]

=> sin²(A). tan(A)

=> sin³(A). sec(A)

Hope this will help you.....