Question

sin 59° + tan 63° complementary angles​

Answer 1

${\huge{\pink{\underline{\underline{Answer}}}}}$

$\bold{Given}$

sin 59° + tan 63° complementary angles.

As We know :

Complementary angle = 90°

Identity :

$\bold{\:\:\:\:\:\:\:\:con[90 - 0 = sin]}$

$\bold{\:\:\:\:\:\:\:\:cot[90 - 0 = tan]}$

So :

$\bold{90 - 59 = 31 = sin}$

$\bold{90 - 63 =27 = tan}$

So the answer is sin 59° + tan 63° is

$\mathrm\blue{sin31° + tan27°}$

Answer 2

Step-by-step explanation:

$sin 59° + tan 63° complementary angles.</p><p></p><p>As We know :</p><p></p><p>Complementary angle = 90°</p><p></p><p>Identity :</p><p></p><p>\bold{\:\:\:\:\:\:\:\:con[90 - 0 = sin]}con[90−0=sin]</p><p></p><p>\bold{\:\:\:\:\:\:\:\:cot[90 - 0 = tan]}cot[90−0=tan]</p><p></p><p>So :</p><p></p><p>\bold{90 - 59 = 31 = sin}90−59=31=sin</p><p></p><p>\bold{90 - 63 =27 = tan}90−63=27=tan</p><p></p><p>So the answer is sin 59° + tan 63° is</p><p></p><p>\mathrm\blue{sin31° + tan27°}sin31°+tan27°</p><p></p><p>$

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