sin(5A+20)=cos(3A+6),A=?
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A= 8⁰
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given, sin(5A+20)=Cos(3A+6)
=Sin(5A+20)=Sin{90-(3A+6)}
= 5A+20=90-3A-6
= 5A+20=84-3A
=5A+3A=84-20
=8A=64
A=8
NOTE- In the second line I use a formula,
cosA= Sin(90-A)
the value of A=8
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