Math, asked by sushilk99135, 2 months ago

Sin^6+cos^6=1-3sin^2A ×cos^2A

Answers

Answered by laasyad

1

Step-by-step explanation:

Given : sin6A + cos6A

sin6A + cos6A = (sin2A)3 + (cos2A)3

(a + b)3 = a3+ b3 + 3ab

(sin2A + cos2A)3 = (sin2A+cos2A)3 – 3sin2Acos2A

sin2A + cos2A = 1

(sin2A + cos2A)3 = 1 – 3sin2Acos2A

sin6A + cos6A = 1 – 3sin2Acos2A

hence proved

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