Question

Sin^6 (theeta)+cos^6 (theeta)+3sin^2 (theeta).cos^2 (theeta)=???
☠Caution :plz give correct answers or i will report it.

Answer 1

Step-by-step explanation:

Sin^6 theta + Cos^6 theta+3Sin²theta*Cos²theta

(Sin²theta)³+(Cos²theta)³+ 3Sin²theta*Cos²theta

=(Sin²theta+Cos²theta) {Sin⁴theta - Sin²theta*

Cos²theta + Cos⁴theta)} + 3Sin²theta*Cos²theta

= Sin⁴theta + Cos⁴theta + 2Sin²theta*Cos²theta

= (Sin²theta)² + (Cos²theta)² + 2(Sin²theta) *

Cos²theta

= (Sin² theta + Cos² theta)²

= (1)²

= 1

I hope it will help you

Answer 2

Step-by-step explanation:

hey avikshit answer to your question is...

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please refer to the attachment..

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hope it helps you and please mark it as brainliest.......