sin^6 theta-cos^6 theta
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Answer:
(Sin^2Θ - Cos^2Θ)(1 - Sin^2Θ*Cos^2Θ)
Step-by-step explanation
(Sin^3Θ)^2 - (Cos^3Θ)^2
(Sin^3Θ + Cos^3Θ)(Sin^3Θ - Cos^3Θ)
(SinΘ + CosΘ)(Sin^2Θ + Cos^2Θ- SinΘ*CosΘ)(SinΘ - CosΘ)(Sin^2Θ + Cos^2Θ + SinΘ*CosΘ)
(SinΘ + CosΘ)(SinΘ - CosΘ)(1 - SinΘ*CosΘ)(1 + SinΘ*CosΘ)
(Sin^2Θ - Cos^2Θ)(1 - Sin^2Θ*Cos^2Θ)
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