Question

sin^6 theta-cos^6 theta​

Answer 1

Answer:

(Sin^2Θ - Cos^2Θ)(1 - Sin^2Θ*Cos^2Θ)

Step-by-step explanation

(Sin^3Θ)^2 - (Cos^3Θ)^2

(Sin^3Θ + Cos^3Θ)(Sin^3Θ - Cos^3Θ)

(SinΘ + CosΘ)(Sin^2Θ + Cos^2Θ- SinΘ*CosΘ)(SinΘ - CosΘ)(Sin^2Θ + Cos^2Θ + SinΘ*CosΘ)

(SinΘ + CosΘ)(SinΘ - CosΘ)(1 - SinΘ*CosΘ)(1 + SinΘ*CosΘ)

(Sin^2Θ - Cos^2Θ)(1 - Sin^2Θ*Cos^2Θ)