Math, asked by revanth62, 10 months ago

sin ^ 6 theta + cos ^ 6 theta + 3 sin ^ 2 theta cos cos ^ 2 theta is equal to 1

Answers

Answered by ismartshankar49

1

Answer:

sin^6theta+cos^6theta+3sin^2thetacos^2theta

is looking as (a+b)^3

we can write (sin^2theta +cos^2theta)^3

as we know sin^2theta+cos^2theta=1

therefore( 1)^3=1

Answered by amansingh3380

0

Answer:

this is the solution of the numerical

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