sin^6 theta + cos^6 theta + 3sin^2 theta*cos^2 theta = 1
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Answered by
1
Answer:
Step-by-step explanation:
it is in the form of a+b whole cube formula
so;
(sin^2 theta +cos^2 theta)³
(1)³ (sin^2 theta +cos^2 theta=1)
rhs =lhs
Abhayraj3030:
i didn't understand
please explain
there are 2 formulae used
you have to learn all identity for solving this type of questions
Answered by
1
Answer:
The proof has been attached below..
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