Sin 6 theta + cos 6 theta barabar 1 - sin square theta into cos square theta
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Prove sin^6 theta + cos^6 theta =1-3sin^2theta cos^ 2theta. ... + cos6ө =1-3sin2өcos2ө (sin2ө)3 + (cos2ө)3 = (sin2ө + cos2ө) 3 − 3 (sin2ө cos2ө)(sin2ө + cos2ө) [since a + b = (a+b)3 − 3ab(a+b)] = 1
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