Sin 60+ Cos (3x-9) = 1, Solve for 'x
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Required Answer:-
sin²60° + cos² (3x - 9°) = 1
cos² (3x - 9°) = 1 - sin²60°
cos² (3x - 9°) = 1 - ¾
cos² (3x - 9°) = ¼
(3x - 9°) = 60°
3x = 69°
x = 23°
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