Question

Sin 60°= 1/2 is true or false

Answer 1

Answer:

it is false

hope it helps you....

Answer 2

Answer:

sin60°

Step-by-step explanation:

Explanation:

Let Δ ABC is equal a equilateral

so , ∠A=∠B=∠C=60 °

let  line AD  bisects angle .

Hence, ABD is a right angle triangle with angle 60° at ∠B.

So, AB = BC and BC = 2BD

 ⇒AB = 2BD

Step 1:

By using pythagoren theorem  for ΔABD

We have , $AB^{2} =AD^{2} +BD^{2}$

⇒$(2BD)^{2}= AD^{2} +BD^{2}$

⇒$4BD^{2} = AD^{2}+ BD^{2}$

⇒$3BD^{2} = AD^{2}$

⇒$AD=\sqrt{3} BD$.

Step 2:

So, sin60° = $\frac{p}{h}=\frac{AD}{AB} =\frac{\sqrt{3} BD}{2BD}$

⇒ sin60° = $\frac{\sqrt{3} }{2}$

Final answer:

Hence ,the  value of sin 60° is $\frac{\sqrt{3} }{2}$ .

So , sin60° = 1/2 is false .