Question

sin 60°/cos^2 45° - 3 tan 30° +5cos 90°​

Answer 1

Answer:

0

Step-by-step explanation:

sin 60°/cos²45°-3tan30°+5cos90°

√3/2*2/1-√3+0

=0

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Answer 2

$\huge \boxed {ANSWER}$

$\sf \large\frac{ \sin(60) }{ { \cos(45) }^{2} - 3 \tan(30) + 5 \cos(90) }$

$= > \sf \large\frac{ \frac{ \sqrt{3} }{2} }{ { (\frac{1}{ \sqrt{2} } )}^{2} - 3( \frac{1}{ \sqrt{3} } ) + 5 \times 0 }$

$= > \sf\large \frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{2} - \sqrt{3} + 0 }$

$= >\sf \large \frac{ \frac{ \sqrt{3} }{2} }{ \frac{1 - \sqrt{3} }{2} }$

$= >\sf\large \frac{ \sqrt{3} }{2} \times \frac{2}{1 - \sqrt{3} }$

$= > \sf \large\frac{ \sqrt{3} }{1 - \sqrt{3} }$

$\large\mathsf{Upon\: rationalizing\: we\: get,}$

$\frac{ \sqrt{3} }{1 - \sqrt{3} } \times \frac{1 + \sqrt{3} }{1 + \sqrt{3} } \\ \\ = > \frac{ \sqrt{3} (1 + \sqrt{3} )}{ {1}^{2} - { \sqrt{3} }^{2} } = - \frac{ \sqrt{3} (1 + \sqrt{3} )}{2}$