Math, asked by rishabh1284, 1 year ago

sin 60°. sec² 45° –3 tan 30° + 4 sin 0

Answers

Answered by TANU81
6
Hi there !

sin 60°. sec² 45° –3 tan 30° + 4 sin 0

 \frac{ \sqrt{3} }{2} \times { \sqrt{2} }^{2} - 3 \times \frac{1}{ \sqrt{3} } + 4 \times 0 \\ \\ \frac{ \sqrt{3} }{2} \times 2 - 3 \times \frac{1}{ \sqrt{3} } + 0 \\ \\ \ \frac{ \sqrt{3} }{1} - \frac{3}{ \sqrt{3} } \\ \\ \\ \frac{0}{ \sqrt{3} } \times<br />\frac{ \sqrt{3} }{ \sqrt{3} } = \frac{0}{3} (we \: ratinalise)<br /> \: \\ = 0

Thanks :)

TANU81: :)
Answered by amritkum360
1

Answer:

Step-by-step explanation:

Root3/2*2-3*1/root3*0

=root3-root3

=0

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