Math, asked by inajain1983, 1 month ago

(sin 60°/sin 30°)*(1+cos 60°)=​

Answers

Answered by sk2813903
0

Answer:

sinAcosB−cosAsinB=sin(A−B)

sin60

°

cos30

°

−cos60

°

sin30

°

=sin(60−30)

°

=sin30

°

Answered by Anonymous
0

The solution is attached in the given image

The values which I used :

sin 60° = √3/2

sin 30° = 1/2

cos 60° = 1/2

Answer: 3√3/2

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