(sin 60°/sin 30°)*(1+cos 60°)=
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Answered by
0
Answer:
sinAcosB−cosAsinB=sin(A−B)
sin60
°
cos30
°
−cos60
°
sin30
°
=sin(60−30)
°
=sin30
°
Answered by
0
The solution is attached in the given image
The values which I used :
sin 60° = √3/2
sin 30° = 1/2
cos 60° = 1/2
Answer: 3√3/2
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