Question

sin 600° cos 330° + cos 120° sin 150º =​

Answer 1

Answer:

I seem it ans is 1

Step-by-step explanation:

if it wrong please answer me

Answer 2

SOLUTION:-

L.H.S

sin150° cos120°+ cos330°sin600°

$= > sin(180 - 30) \degree \: cos(180 - 60) \degree \: + cos(360 - 30) \degree \: sin(2 \times 360 - 60) \degree \\ \\ = > sin30 \degree( - cos60 \degree) + cos30 \degree( - sin60 \degree) \\ \\ = > \frac{1}{2} ( - \frac{1}{2} ) + \frac{ \sqrt{3} }{2} ( \frac{ - \sqrt{3} }{2} ) \\ \\ = > - \frac{1}{4} - \frac{3}{4} \\ \\ = > \frac{ - 1 - 3}{4} = - \frac{4}{4} \\ \\ = > - 1. = > </strong><strong>R</strong><strong>.</strong><strong>H</strong><strong>.</strong><strong>S</strong><strong>$

Hope it helps ☺️