Question

sin 60³+sin40²/sin60³-sin40²=

Answer 1

The answer is:

2.97340480535

Hope it helps!

Answer 2

$\underline{\textsf{Solution :}}$

$\mathsf{Now,\:\frac{sin60^{3}+sin40^{2}}{sin60^{3}-sin40^{2}}}$

$\mathsf{= \frac{sin216000+sin1600}{sin216000-sin1600}}$

$\mathsf{= \frac{sin\{(600*360)+0\}+sin\{(4*360)+160\}}{ sin\{(600*360)+0\}-sin\{(4*360)+160\}}}$

$\mathsf{= \frac{sin0-sin160}{sin0+sin160}}$

$\mathsf{= \frac{-sin160}{sin160}}$

$\mathsf{= - 1}$

$\to \boxed{\mathsf{\frac{sin60^{3}+sin40^{2}}{sin60^{3}-sin40^{2}}=-1}}$