Question

sin 60degree cos45 degree +cos 60 degree sin45degree =root 3+1divide by 2 root 2 hence proved

Answer 1

heya friend ✋✋

here's your answer (︶^︶)

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$\sin(60) \times \cos(45) + \cos(60 ) \times \sin(45) = \frac{ \sqrt{3} + 1}{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} }{2} \times \frac{1}{ \sqrt{2} } + \frac{1}{2} \times \frac{1}{ \sqrt{2} } = \frac{ \sqrt{3} + 1}{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} }{2 \sqrt{2} } + \frac{1}{2 \sqrt{2} } = \frac{ \sqrt{3} + 1 }{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} + 1 }{2 \sqrt{2} } = \frac{ \sqrt{3} + 1 }{2 \sqrt{2} }$

hence,proved

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^_^hope it helps u ^_^

Answer 2

Answer:

\sin(60) \times \cos(45) + \cos(60 ) \times \sin(45) = \frac{ \sqrt{3} + 1}{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} }{2} \times \frac{1}{ \sqrt{2} } + \frac{1}{2} \times \frac{1}{ \sqrt{2} } = \frac{ \sqrt{3} + 1}{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} }{2 \sqrt{2} } + \frac{1}{2 \sqrt{2} } = \frac{ \sqrt{3} + 1 }{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} + 1 }{2 \sqrt{2} } = \frac{ \sqrt{3} + 1 }{2 \sqrt{2} }  

Step-by-step explanation:

\sin(60) \times \cos(45) + \cos(60 ) \times \sin(45) = \frac{ \sqrt{3} + 1}{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} }{2} \times \frac{1}{ \sqrt{2} } + \frac{1}{2} \times \frac{1}{ \sqrt{2} } = \frac{ \sqrt{3} + 1}{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} }{2 \sqrt{2} } + \frac{1}{2 \sqrt{2} } = \frac{ \sqrt{3} + 1 }{2 \sqrt{2} } \\ = > \frac{ \sqrt{3} + 1 }{2 \sqrt{2} } = \frac{ \sqrt{3} + 1 }{2 \sqrt{2} }