Sin 62 sin 28° - cos 62 cos 28°
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Answered by
10
Answer:
0
Step-by-step explanation:
cos(a+b)=cosa.cosb - sina.sinb
-[cos(a+b)]=sina.sinb - cosa.cosb
so you have a -cos(a+b) at your hands.
a=62 b =28
62+28=90.
-cos90=0, cos90 is already zero.
Answered by
1
Answer:
Sin 62 sin 28° - cos 62 cos 28°
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