Question

sin 63° cos 27° + cos 63° sin 27°​

Answer 1

Answer:

Value of sin 63° cos 27° + cos 63°sin 27°= 1

Step-by-step explanation:

Value of sin 63° cos 27° + cos 63°sin 27° = sin( 63°+27°)

Since , Sin A cos B + sin B cos A = sin(A+B)

                  = sin 90°

                  = 1

Therefore,

Value of sin 63° cos 27° + cos 63°sin 27°= 1

Answer 2

Answer:

sin63=sin(90-27)

=cos 27

cos63=cos(90-27)

=sin 27

on substituting the value

(cos27)^2+ (sin27)^2=1

=1(ans)

(we know that sin square x +cos square x=1)

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