Math, asked by tanishasaha806, 9 months ago

Sin 63°cos27°+ cos 63º Sin 27°=1​

Answers

Answered by zoya0710
1

Step-by-step explanation:

sin 63°.sin (90-27)+cos63°.cos (90-27)°

=sin63°.sin63°+ cos63°.cos63°

=sin^263°+cos^2 63°

using sin^2 A+ cos^2 A =1

=1

HOPE IT WILL HELP

Answered by princesinghvi08
1

ANSWER :

sin63°cos27° + cos63°sin27° = 1

sin63° . sin(90-27)° + cos63° . cos(90-67)

sin63° . sin63° + cos63° . cos63°

 {sin}^{2}  + {cos}^{2}  = 1

hence, sin63°cos27° + cos63°sin27° = 1

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